Calculus Level 5

$\large{\sum _{ k=0 }^{ \infty }{ \frac { (4k)!(1103+26390k) }{ { (k!) }^{ 4 }{ 396 }^{ 4k } } } =\frac { A }{ \pi \sqrt { B } } }$

If the above summation can be expressed as shown above for some positive integers $$A$$ and $$B$$, find $$A+B$$.

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