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C=∫03π[1−cos2x121−sin2x12+1] dxC = \int_0^{3\pi} \bigg [ \frac{1 - \cos^2{\frac{x}{12}}} {1 - \sin^2{\frac{x}{12}}} + 1 \bigg ] \, \mathrm{d}xC=∫03π[1−sin212x1−cos212x+1]dx If the value of 2+C1442 + \frac{C}{144}2+144C is in the form a/ba/ba/b where aaa and bbb are positive coprime integers and enter a+ba+ba+b as your answer.
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