A square of side length 10 is placed so that its corner, \(A,\) is *exactly at the center* of a square of side length 6. The squares intersect at point \(B\) as shown; the length of line segment \(BC\) (connecting \(B\) to a corner of the smaller square) is 5.

**What is the area of the green quadrilateral?**

If you get stuck, try drawing some lines on the figure to help you out.

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