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DeMoivre's Theorem Year 2014

Given

z=[sin(π2014)+icos(π2014)]2014, z = \left[ \sin\left(\frac{\pi}{2014}\right) + i \cos\left(\frac{\pi}{2014}\right)\right]^{2014},

find 1z2014 \dfrac1{z^{2014}} .

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