# Dependent on $$m$$?

For each number $$n$$, we define the "Digital Sum" as sum of the digits of $$n$$ and repeat the process until the result is a single digit number.

Example :

For $$1234 \rightarrow 1 + 2 + 3 + 4 \rightarrow 10 \rightarrow 1 + 0 = 1$$

Find the digital sum of $$\underset { m \text{ times} }{ \underbrace { 4617\ldots 4617} }$$.

$$m > 0$$.

Inspired by 2016 Digital Sum

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