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Calculus Level 2

Find the derivative of function \(y = x^x\).

\[y'=x^x (\ln x + 1) \] \[y'=x (\ln x + 1) \] \[y'=x^{x+1} (\ln x + 1) \] \[y'=x\ln x \]

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by Sopheak Seng

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