Let \(A=\left| \begin{matrix} { x }^{ 2 } & 6 & 8 \\ 3 & y^{ 2 } & 9 \\ 4 & 5 & { z }^{ 2 } \end{matrix} \right| ,B=\left| \begin{matrix} 2x & 3 & 5 \\ 2 & 2y & 6 \\ 1 & 4 & 2z-3 \end{matrix} \right| \)

If \(\text{trace}(A)=\text{trace}(B)\), then \(x+y+z\) is equal to

The first part is here

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