Can you remove the log?
Algebra
Level
4
\[\large\begin{cases} (3x)^{\log 3} = (4y)^{\log 4}\\ 4^{\log x}= 3^{\log y}\end{cases}\]
Given the system of equations above, find the value of \( \dfrac{1}{x}+\dfrac{1}{y} \).
by
Aneesh Kundu