# Can you remove the log?

Algebra Level 4

$\large\begin{cases} (3x)^{\log 3} = (4y)^{\log 4}\\ 4^{\log x}= 3^{\log y}\end{cases}$

Given the system of equations above, find the value of $$\dfrac{1}{x}+\dfrac{1}{y}$$.

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