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{x=a(t−sint)y=a(1−cost)\large \begin{cases} x = a(t-\sin t) \\ y = a(1-\cos t) \end{cases}⎩⎨⎧x=a(t−sint)y=a(1−cost)
Given the above, find dydx\dfrac {dy}{dx}dxdy at t=π2t= \dfrac \pi2t=2π.
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