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[dd(cosx)(∑n=1100cosnx)]x=2π= ? \large \left[ \frac { d }{ d\left( \cos { x } \right) } \left( \sum _{ n=1 }^{ 100 }{ \cos { nx } } \right) \right] _{ { x=2\pi }} =\, ?⎣⎡d(cosx)d⎝⎛n=1∑100cosnx⎠⎞⎦⎤x=2π=?
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