Differentiating for fun!

Calculus Level 1

If y=(1+x)(1+x2)(1+x4)...(1+x2n) y=\left( 1+x \right) \left( 1+{ x }^{ 2 } \right) \left( 1+{ x }^{ 4 } \right) ...(1+{ x }^{ { 2 }^{ n } }) , thendydx \frac { dy }{ dx } at x=0x = 0 is:

×

Problem Loading...

Note Loading...

Set Loading...