# Difficult Trigo

Geometry Level pending

If we have $\tan\dfrac{\pi}{13}\tan\dfrac{2{\pi}}{13}\tan\dfrac{3{\pi}}{13}\cdots\tan\dfrac{6{\pi}}{13}=\dfrac {\sqrt{a}}{b}$ where $$\gcd(a,b)=1$$, then find the value of $$a+b$$.

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