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a2+b2+c2a+b+c=d\dfrac{a^2 + b^2 + c^2}{a+b+c} = da+b+ca2+b2+c2=d
Let a,b,c,da,b,c,da,b,c,d be distinct digits between 111 and 999 inclusively, satisfying the equation above. What is the sum of all possible values of d?d?d?
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