Disc Partitioned - 2

I suggest you check Disc Partitioned - 1 before you try this question.

There is a circular disc of radius \(R\) which is undergoing pure rolling on a surface.

If \( V\) is the velocity of center of mass of the disc, let a part of the disc be the collection of points on the disc for which the magnitude of velocity is less than \(V\) in SI units.

Thus the disc is now partitioned. That is divided into two parts.

Find the ratio of the kinetic energies of the two parts of the disc.

The ratio must be greater than 1 i.e. the ratio of the more energetic part to the lesser one is required.

You may use a calculator in the end for the decimal answer.


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