Distance to side

Geometry Level pending

\(ABC\) is a right triangle with \(m\angle C=90^{\circ}\). \(AC=10\text{ units}^2\) and \(BC=24\text{ units}^2\). Point \(P\) is located inside \(ABC\) such that the distance from \(P\) to \(AB\) is twice the distance from \(P\) to \(AC\), and the distance from \(P\) to \(AC\) is twice the distance from \(P\) to \(BC\). In \(\text{units}^2\), what is the distance from \(P\) to \(AB\)?

Express your answer as a decimal to the nearest hundredth.

×

Problem Loading...

Note Loading...

Set Loading...