# Divisible by this year??? v2015 (Part 3: A Jinx from the future!!!)

Find the minimum value of $$n$$ where $$n$$ is an integer such that the number of trailing zeroes of $(n+20)! \times (n + 16)!$ is divisible by $$2015$$

($$201500000$$ has $$5$$ trailing zeroes while $$2000015000$$ has $$3$$)

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