Following are the first 10 terms of the sequence of the 2016-digit numbers with all their digits repeating in ascending (or increasing) order.

`0123456789012345678901234567890...123456789012345`

`123456789012345678901234567890...1234567890123456`

`23456789012345678901234567890...12345678901234567`

`3456789012345678901234567890...123456789012345678`

`456789012345678901234567890...1234567890123456789`

`56789012345678901234567890...12345678901234567890`

`6789012345678901234567890...123456789012345678901`

`789012345678901234567890...1234567890123456789012`

`89012345678901234567890...12345678901234567890123`

`9012345678901234567890...123456789012345678901234`

What are the last 3 digits of the \(2292016^\text{th}\) term of the sequence?

**Clarifications:**

I have considered the first number as a 2016-digit number as well, the number has one leading zero and then the pattern continues

Each of the numbers has a repeating part \( \dots 0123456789 \dots \)

Try Part 2 of this problem as well.

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