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limx→0+p+e1x1+qe1x=2 \large \displaystyle\lim_{x \rightarrow 0^{+}} \dfrac{ p + e^{\frac{1}{x}}}{ 1 + qe^{\frac{1}{x}} } = 2x→0+lim1+qex1p+ex1=2
Find qqq.
Details: p,q p , q p,q ϵ\epsilonϵ ℜ\Reℜ
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