The mass of an elephant can be many thousands of kilograms and their feet can be over a meter around. If a \(6000~\mbox{kg}\) elephant is standing and its feet each have a circumference of \(1.34~\mbox{m}\), how much pressure **in pascals** does one foot exert on the ground? The pressure, for those who may be unaware, is the total force exerted divided by the area over which the force is exerted, i.e. \(p=F/A\).

**Details and assumptions**

- The acceleration due to gravity is \(-9.8~\mbox{m/s}^2\).
- You may assume the weight is distributed evenly between the four feet.

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