**True or False?**

By the law of indices, we know that $a^3 = a \times a \times a$ and $a^2 = a\times a$.

This also means that $\dfrac{a^3}{a^2} = \dfrac{a\times a \times a}{a\times a} = \dfrac{a\times \bcancel a \times \bcancel a}{\bcancel a\times \bcancel a} = a$.

Let $a = 0$, we get $\dfrac{0^3}{0^2} = 0$.

Since $0^3 = 0\times0\times0 = 0$ and $0^2 = 0\times0 = 0$, we can conclude that $\dfrac00 = 1$.

×

Problem Loading...

Note Loading...

Set Loading...