# Don't think about wheel theory!

Algebra Level 1

True or False?

By the law of indices, we know that $$a^3 = a \times a \times a$$ and $$a^2 = a\times a$$.

This also means that $$\require{cancel} \dfrac{a^3}{a^2} = \dfrac{a\times a \times a}{a\times a} = \dfrac{a\times \bcancel a \times \bcancel a}{\bcancel a\times \bcancel a} = a$$.

Let $$a = 0$$, we get $$\dfrac{0^3}{0^2} = 0$$.

Since $$0^3 = 0\times0\times0 = 0$$ and $$0^2 = 0\times0 = 0$$, we can conclude that $$\dfrac00 = 1$$.

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