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Compute the following integral
M=∫01sin(2x)x dx+∫02ln(x)cos(x) dxM=\displaystyle \int_{0}^{1} \dfrac{\sin(2x)}{x}~\Bbb{d}x+\int_{0}^{2} \ln(x)\cos(x)~\Bbb{d}xM=∫01xsin(2x) dx+∫02ln(x)cos(x) dx
Input your answer as ⌊100M⌋\lfloor 100M\rfloor⌊100M⌋
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