Forgot password? New user? Sign up

Existing user? Log in

Let $A=\sqrt{2}^{\sqrt{2}^{\sqrt{2}^{\cdot^{\cdot^{\cdot}}}}}$ and $B = ^{\sqrt[{}^\ddots\!\!\sqrt{2}]{2}}\!\!\!\!\!\sqrt{2}$

Then it is true that:

Note: $B$ is not a nested tetration.

Problem Loading...

Note Loading...

Set Loading...