Forgot password? New user? Sign up
Existing user? Log in
Let A=222⋅⋅⋅ A=\sqrt{2}^{\sqrt{2}^{\sqrt{2}^{\cdot^{\cdot^{\cdot}}}}} A=222⋅⋅⋅ and B=2⋱ 2 2 B = ^{\sqrt[{}^\ddots\!\!\sqrt{2}]{2}}\!\!\!\!\!\sqrt{2} B=⋱222
Then it is true that:
Note: BBB is not a nested tetration.
Problem Loading...
Note Loading...
Set Loading...