# Double Diagonal Power Tower

Algebra Level 3

Let $A=\sqrt{2}^{\sqrt{2}^{\sqrt{2}^{\cdot^{\cdot^{\cdot}}}}}$ B=^\sqrt[{}^\ddots\!\!\sqrt{2}]{2}\!\!\!\!\!\sqrt{2} Then it is true that:

Note: $B$ is not a nested tetration.

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