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Evaluate the limit for x∉Qx \notin \mathbb{Q}x∈/Q :
limn→∞limm→∞(cos(m!πx))2n−1(cos(m!πx))2n+1\large \lim_{n \to \infty} \lim_{m \to \infty} \dfrac{(\cos(m!\pi x))^{2n}-1}{(\cos(m! \pi x))^{2n}+1} n→∞limm→∞lim(cos(m!πx))2n+1(cos(m!πx))2n−1
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