# Double summation continues

Calculus Level 5

$\displaystyle \sum_{m=1}^{\infty} \sum_{k=0}^{\infty} \dfrac{(-1)^m}{(2k + 1)^2 + m^2} = \dfrac{\pi \text{ ln } a - \pi^b}{c^d}$

• Find $$13\times(a + b + c + d)$$

• $$a,b,c$$ are prime numbers and $$d$$ is an integer

• $$\text{ ln }$$- natural logarithm

×