Double Wedge! (Easy Version)

Find the maximum\color{#D61F06}{maximum} height reached by the ball on the second\color{#D61F06}{second} wedge(in m), if above system is released from rest.

Conditions in statement

  • All surfaces are smooth\color{#D61F06}{smooth}.

  • Mass of ball and the wedges are same\color{#D61F06}{same} and equal to m\color{#D61F06}{m}

  • Wedges are not\color{#D61F06}{not} fixed and can slide on the ground.

  • Height of ball on first wedge is 10m\color{#D61F06}{10m}

  • Take acceleration due to gravity g=10ms2\color{#D61F06}{g = 10 ms^{-2}}

  • Ball changes direction elastically each time and moves always parallel to the surface in contact.


My all time inspiration Aniket Sanghi


All of my problems are original\color{#3D99F6}{original}

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