# Dubya

Algebra Level 4

$y = |x| + 2|x+1| - 3|x+2| + 4|x+3|$

It's given that $$y = \mathscr{E}$$ has only two intersections with the above equation. What is the minimum integral value of $$\mathscr{E}$$ that meets this condition?

 Notation: $$| \cdot |$$ denotes the absolute value function.

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