An object is thrown from a height of 200 m and simultaneously one other stone is projected upwards with a velocity of 50 m per second .

[Take g as 10 \( m/s^{2}\)]

Find the height where they meet . (Height is measured from the ground)

Find also the time after which the two stones meet .

Enter the answer as how close the projected stone move towards the meeting point per second.

I mean - Height/time

×

Problem Loading...

Note Loading...

Set Loading...