# Easy NT!

If (p,q) satisfy the condition that p divides \({q}^{2}-4\) and q divides \({p}^{2}-1\), then find the sum of all such primes.

**Details**

If the ordered pair of such primes are \(({p}_{1}, {q}_{1}), ({p}_{2},{q}_{2}),.... ({p}_{n}, {q}_{n})\), then give your answer as \({p}_{1} + {q}_{1} + {p}_{2} + {q}_{2}+ .... +{p}_{n} + {q}_{n}\)