Out of 10001 tickets numbered consecutively, 3 are drawn at random .
Find the chance that the numbers on them are in Arithmetic Progression .
The answer is of the form \( \frac{l}{k} \) .
Find \( k - l \) where \(k\) and \(l\) are co-prime integers.
HINT : You might consider solving for \(2n + 1\) tickets .
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