Easy to guess, somewhat hard to prove!
Algebra
Level
2
If \(x^{2}\)+\(a^{2}\) = \(y^{2}\)+\(b^{2}\) = (\(a\times x\)) + (\(b\times y\)) = 1,
then the numerical value of \(a^{2}\) + \(b^{2}\) is
by
jaiveer shekhawat