# Easy to guess, somewhat hard to prove!

Algebra Level 2

If $$x^{2}$$+$$a^{2}$$ = $$y^{2}$$+$$b^{2}$$ = ($$a\times x$$) + ($$b\times y$$) = 1,

then the numerical value of $$a^{2}$$ + $$b^{2}$$ is

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