# Electric circuit

The above diagram is a circuit that consists of a power supply of voltage $$V$$ and two capacitors A and B with capacitances $$C$$ and $$2C$$, respectively. Suppose that the switch $$S_1$$ is closed and the switch $$S_2$$ is open, and sufficient time passes until the quantity of the electric charge on the capacitor A becomes $$Q.$$ In this state, we open the switch $$S_1$$ and close the switch $$S_2$$ and let sufficient time pass. Then what will be the ratio of the quantities of the electric charges on the capacitors A and B, i.e. $$Q_A:Q_B?$$

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