# Electrochemistry...#1

Chemistry Level pending

We have taken a saturated solution of $$\text{AgBr}$$, whose $$K_{sp}$$ is $$12 \times 10^{-14}$$. If $$10^{-7}\text{ M}$$ of $$\text{AgNO}_{3}$$ is added to 1 L of this solution, what would be the conductivity (specific conductance) of the solution?

Given, $\lambda^{o}_{(Ag ^{+})} = 6 \times 10^{-3} Sm^{2} mol^{-1}$ $\lambda^{o}_{(Br ^{-})} = 8 \times 10^{-3} Sm^{2} mol^{-1}$ $\lambda^{o}_{(NO_{3} ^{-})} = 7 \times 10^{-3} Sm^{2} mol^{-1}$

Express the answer in terms of $$10^{-7} Sm^{-1} units$$