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In the above figure, points (E,D,F) (E,D,F ) (E,D,F) and (B,A,F) (B,A,F) (B,A,F) are collinear, and EC‾=CD‾=BC‾ \overline{EC} = \overline{CD} = \overline{BC} EC=CD=BC. Also, CB⊥BA CB \bot BA CB⊥BA. The length of ED ED ED is a a a, and the length of DF DF DF is b b b. Then find the length of FB FB FB in terms of aaa and bbb.
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