# Elementary calculus 5

Calculus Level 1

$$f(p) = \begin{cases} \frac{ \sqrt p}{p^2} \text {if}, p = 4 \\ \frac{p^2}{\sqrt p} \text{if}, -2 \leq p < 4 \\ \sqrt[3]{p^2 + 2p}, \text{if}, 4<p \leq 6 \end{cases}$$

Evaluate $$\displaystyle \lim_{p \to 5} f(p)$$.

Submit your answer to the nearest hundred thousand

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