let a number be 'a'.

let its sum of the digits be 'x'.

Condition: Now if I add up 'x' and 'a' and subtract twice the last digit of 'a' from it, then i get a number divisible by 11.

For example: a=132, then x=3+2+1=6

```
Now a+x-2(2)=138-4=134
and 134 is not divisible by 11.
```

Find the sum of all the numbers satisfying the above condition.

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