let a number be 'a'.
let its sum of the digits be 'x'.
Condition: Now if I add up 'x' and 'a' and subtract twice the last digit of 'a' from it, then i get a number divisible by 11.
For example: a=132, then x=3+2+1=6
Now a+x-2(2)=138-4=134 and 134 is not divisible by 11.
Find the sum of all the numbers satisfying the above condition.