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Geometry Level 4

k=115cis2k1(π36) \large\sum_{k=1}^{15} \textrm{cis}^{2k-1}\left( \frac{\pi}{36} \right)

Compute the imaginary part of the summation above.

Notation

  • cis θ=cosθ+isinθ \textrm{cis }\theta = \cos \theta + i \sin\theta .
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