Equating series of Sums and Products!

\[\large{\sum_{k=1}^{2015} 2^{k-1} (x_k)^{2015} = 2014 \prod_{k=1}^{2015} x_k}\]

For all integers \(x_i\), find the sum of all \(x_i\)(s), where \(\leq i \leq 2015 \) such that the above equation is satisfied.

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