Equilibrium of JEE!

A straight metal rod of length 3L3L is bent through the right angle as shown. The bent rod is then placed on a rough horizontal table. A light string is attached to the vertex of the right angle. The string is then pulled horizontally so that rod slides at a constant velocity vv .

Find the angle α\alpha (in degrees) that the side 2L2L would make with the string.

Details and Assumptions

  • Mass density of rod: ρr=10 kg/m\rho_r= 10\text{ kg/m},
  • Length: L=10 mL = 10\text{ m},
  • Velocity: v=10 m/sv= 10 \text{ m/s}.
This is asked in very old IIT JEE exam !
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