Euler all around!

Let \(\phi(n)\) denote the number of positive integers which are less than or equal to \(n\) and relatively prime to \(n\).Let \(d(n)\) denote the number of positive integral divisors of \(n\).Find the sum of all odd integers \(n\le 5000\) such that \(n| \phi(n)d(n)\).

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