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a2+b2+c23(ab+ac+bc)\frac{a^2+b^2+c^2}{3(ab+ac+bc)}3(ab+ac+bc)a2+b2+c2
For how many ordered triples of positive integers (a,b,c)≤2014(a, b, c) \leq 2014(a,b,c)≤2014 is the expression above an integer?
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