Exploring Divisor Function 3

\[\sum _{n=1}^{\infty}\frac{d\left(2048n\right)}{n^2}=\frac{A\pi^B}{C}\]

Where \(d(n)\) counts the number of divisors of \(n\). Find \(A+B+C\)


Hint: 2048 is 2 to the power of 11. 2 is a prime.

This problem is part of the set Exploring the divisor function
×

Problem Loading...

Note Loading...

Set Loading...