# Exploring Divisor Function 4

$\sum _{n=1}^{\infty}\frac{d\left(2016n\right)}{n^2}=\frac{A\pi^B}{C}$

Where $$d(n)$$ counts the number of divisors of $$n$$. Find $$A+B+C$$

Hint: Prime factorise 2016

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