Factorial problem again !!

Determine the number of terminating zeroes in 8000!8000!


Note:

  • 10000 has 4 terminating zeroes while 1000100 has only 2.
  • n!=n×(n1)×(n2)××3×2×1.n! = n \times (n-1) \times (n-2) \times \cdots \times 3 \times 2 \times 1.
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