# Factorial problem by Ashu Dablo

Find the largest positive integer n, such that $$n!$$ can be expressed as the product of $$(n-2^{11})$$ consecutive integers.

Let a positive integer $$x$$ be $$\equiv n \pmod{71\times 73\times 79}$$

Find $$x$$ $$\pmod{41\times 47}$$

x is the remainder when n is divided by 409457 (409457=71x73x79).

The answer is the remainder when x is divided by 1927. (1927=41*47)

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