Given the equation |3A| - \(log 10^{27}\) + y! = \(\frac{y!}{x! (y - x)!}\),

where A is and indentity matrix of order 3x3,

|3A| is the determinant of the matrix 3A,

(log 5 = 0.7), (log 3 = 0.45), (log 2 = 0.3) and (x! = x (x - 1)!).

First, find the two possible values of x (m and n), such as (y = 2x).

Then, consider that (m > n), (m = a + b), (n = a - b), (3m + 2n = c)

and find the value of (4a + 2b + c²).

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