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1!×3!=(1+2)!{1}1!×3!×5!=(1+2+3)!{2}1!×3!×5!×7!=(1+2+3+4)!{3}1!×3!×5!×7!×9!=(1+2+3+4+5)!{4} \begin{array} { l l r } 1! \times 3! & = (1+2)! & \{1\} \\ 1! \times 3! \times 5! & = (1+2+3)! & \{2\} \\ 1! \times 3! \times 5! \times 7! & = (1+2+3 + 4)! & \{3\} \\ 1! \times 3! \times 5! \times 7! \times 9! & = (1+2+3 + 4 + 5)! \quad\quad & \{4\} \\ \end{array} 1!×3!1!×3!×5!1!×3!×5!×7!1!×3!×5!×7!×9!=(1+2)!=(1+2+3)!=(1+2+3+4)!=(1+2+3+4+5)!{1}{2}{3}{4}
Which of the above equations is false?
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