A pendulum clock is mounted in an elevator car which starts going up at a uniform acceleration \(a\), (\(a<g\)). After ascending a height \(h\) above the starting point direction of acceleration is reversed keeping its magntiude constant . Find time after start of motion of the car when clock will show the right time again .

Details And Assumptions-

a = 5 m/sec^2

g = 10 m/sec^2

h = 10 m .

give your answer is seconds

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