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∫01x2(1−x)4ln(1x) dx \large \displaystyle \large \int_{0}^{1} x^{2} (1-x)^4 \ln \left(\frac{1}{x}\right ) \, dx ∫01x2(1−x)4ln(x1)dx
If the value of the integral above is equal to ab \dfrac abba, where aaa and bbb are coprime positive integers, find a+ba+ba+b.
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