A function f:Z→Z, has the following conditions
f(n)=2f(n−1)+2f(2n), if n is even
f(n)=2f(n)+2f(2n−1), if n is odd
If f(1)=2, find f(3)f(4)f(10)f(12)f(18)f(52)f(60)f(502)f(2011)f(2012)f(2013)f(2014)
This problem is part of the Figure-It-Out Function! series