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Find the number of real xxx satisfying the equation {x}⌊x⌋−2⌊x⌋={x}−1 \{x\} \lfloor x \rfloor- 2\lfloor x \rfloor = \{x\} -1{x}⌊x⌋−2⌊x⌋={x}−1.
Notations:
{⋅}\{\cdot \}{⋅} denotes the fractional part function.
⌊⋅⌋\lfloor \cdot \rfloor⌊⋅⌋ denotes the floor function.
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